Optimal. Leaf size=201 \[ -\frac{33 e^2 (d+e x)^{7/2}}{8 b^3 (a+b x)}+\frac{77 e^3 (d+e x)^{3/2} (b d-a e)}{8 b^5}+\frac{231 e^3 \sqrt{d+e x} (b d-a e)^2}{8 b^6}-\frac{231 e^3 (b d-a e)^{5/2} \tanh ^{-1}\left (\frac{\sqrt{b} \sqrt{d+e x}}{\sqrt{b d-a e}}\right )}{8 b^{13/2}}-\frac{11 e (d+e x)^{9/2}}{12 b^2 (a+b x)^2}-\frac{(d+e x)^{11/2}}{3 b (a+b x)^3}+\frac{231 e^3 (d+e x)^{5/2}}{40 b^4} \]
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Rubi [A] time = 0.130738, antiderivative size = 201, normalized size of antiderivative = 1., number of steps used = 9, number of rules used = 5, integrand size = 28, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.179, Rules used = {27, 47, 50, 63, 208} \[ -\frac{33 e^2 (d+e x)^{7/2}}{8 b^3 (a+b x)}+\frac{77 e^3 (d+e x)^{3/2} (b d-a e)}{8 b^5}+\frac{231 e^3 \sqrt{d+e x} (b d-a e)^2}{8 b^6}-\frac{231 e^3 (b d-a e)^{5/2} \tanh ^{-1}\left (\frac{\sqrt{b} \sqrt{d+e x}}{\sqrt{b d-a e}}\right )}{8 b^{13/2}}-\frac{11 e (d+e x)^{9/2}}{12 b^2 (a+b x)^2}-\frac{(d+e x)^{11/2}}{3 b (a+b x)^3}+\frac{231 e^3 (d+e x)^{5/2}}{40 b^4} \]
Antiderivative was successfully verified.
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Rule 27
Rule 47
Rule 50
Rule 63
Rule 208
Rubi steps
\begin{align*} \int \frac{(d+e x)^{11/2}}{\left (a^2+2 a b x+b^2 x^2\right )^2} \, dx &=\int \frac{(d+e x)^{11/2}}{(a+b x)^4} \, dx\\ &=-\frac{(d+e x)^{11/2}}{3 b (a+b x)^3}+\frac{(11 e) \int \frac{(d+e x)^{9/2}}{(a+b x)^3} \, dx}{6 b}\\ &=-\frac{11 e (d+e x)^{9/2}}{12 b^2 (a+b x)^2}-\frac{(d+e x)^{11/2}}{3 b (a+b x)^3}+\frac{\left (33 e^2\right ) \int \frac{(d+e x)^{7/2}}{(a+b x)^2} \, dx}{8 b^2}\\ &=-\frac{33 e^2 (d+e x)^{7/2}}{8 b^3 (a+b x)}-\frac{11 e (d+e x)^{9/2}}{12 b^2 (a+b x)^2}-\frac{(d+e x)^{11/2}}{3 b (a+b x)^3}+\frac{\left (231 e^3\right ) \int \frac{(d+e x)^{5/2}}{a+b x} \, dx}{16 b^3}\\ &=\frac{231 e^3 (d+e x)^{5/2}}{40 b^4}-\frac{33 e^2 (d+e x)^{7/2}}{8 b^3 (a+b x)}-\frac{11 e (d+e x)^{9/2}}{12 b^2 (a+b x)^2}-\frac{(d+e x)^{11/2}}{3 b (a+b x)^3}+\frac{\left (231 e^3 (b d-a e)\right ) \int \frac{(d+e x)^{3/2}}{a+b x} \, dx}{16 b^4}\\ &=\frac{77 e^3 (b d-a e) (d+e x)^{3/2}}{8 b^5}+\frac{231 e^3 (d+e x)^{5/2}}{40 b^4}-\frac{33 e^2 (d+e x)^{7/2}}{8 b^3 (a+b x)}-\frac{11 e (d+e x)^{9/2}}{12 b^2 (a+b x)^2}-\frac{(d+e x)^{11/2}}{3 b (a+b x)^3}+\frac{\left (231 e^3 (b d-a e)^2\right ) \int \frac{\sqrt{d+e x}}{a+b x} \, dx}{16 b^5}\\ &=\frac{231 e^3 (b d-a e)^2 \sqrt{d+e x}}{8 b^6}+\frac{77 e^3 (b d-a e) (d+e x)^{3/2}}{8 b^5}+\frac{231 e^3 (d+e x)^{5/2}}{40 b^4}-\frac{33 e^2 (d+e x)^{7/2}}{8 b^3 (a+b x)}-\frac{11 e (d+e x)^{9/2}}{12 b^2 (a+b x)^2}-\frac{(d+e x)^{11/2}}{3 b (a+b x)^3}+\frac{\left (231 e^3 (b d-a e)^3\right ) \int \frac{1}{(a+b x) \sqrt{d+e x}} \, dx}{16 b^6}\\ &=\frac{231 e^3 (b d-a e)^2 \sqrt{d+e x}}{8 b^6}+\frac{77 e^3 (b d-a e) (d+e x)^{3/2}}{8 b^5}+\frac{231 e^3 (d+e x)^{5/2}}{40 b^4}-\frac{33 e^2 (d+e x)^{7/2}}{8 b^3 (a+b x)}-\frac{11 e (d+e x)^{9/2}}{12 b^2 (a+b x)^2}-\frac{(d+e x)^{11/2}}{3 b (a+b x)^3}+\frac{\left (231 e^2 (b d-a e)^3\right ) \operatorname{Subst}\left (\int \frac{1}{a-\frac{b d}{e}+\frac{b x^2}{e}} \, dx,x,\sqrt{d+e x}\right )}{8 b^6}\\ &=\frac{231 e^3 (b d-a e)^2 \sqrt{d+e x}}{8 b^6}+\frac{77 e^3 (b d-a e) (d+e x)^{3/2}}{8 b^5}+\frac{231 e^3 (d+e x)^{5/2}}{40 b^4}-\frac{33 e^2 (d+e x)^{7/2}}{8 b^3 (a+b x)}-\frac{11 e (d+e x)^{9/2}}{12 b^2 (a+b x)^2}-\frac{(d+e x)^{11/2}}{3 b (a+b x)^3}-\frac{231 e^3 (b d-a e)^{5/2} \tanh ^{-1}\left (\frac{\sqrt{b} \sqrt{d+e x}}{\sqrt{b d-a e}}\right )}{8 b^{13/2}}\\ \end{align*}
Mathematica [C] time = 0.0252909, size = 52, normalized size = 0.26 \[ \frac{2 e^3 (d+e x)^{13/2} \, _2F_1\left (4,\frac{13}{2};\frac{15}{2};-\frac{b (d+e x)}{a e-b d}\right )}{13 (a e-b d)^4} \]
Antiderivative was successfully verified.
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Maple [B] time = 0.209, size = 719, normalized size = 3.6 \begin{align*} \text{result too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: ValueError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [B] time = 2.0346, size = 2140, normalized size = 10.65 \begin{align*} \text{result too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [B] time = 1.22319, size = 663, normalized size = 3.3 \begin{align*} \frac{231 \,{\left (b^{3} d^{3} e^{3} - 3 \, a b^{2} d^{2} e^{4} + 3 \, a^{2} b d e^{5} - a^{3} e^{6}\right )} \arctan \left (\frac{\sqrt{x e + d} b}{\sqrt{-b^{2} d + a b e}}\right )}{8 \, \sqrt{-b^{2} d + a b e} b^{6}} - \frac{267 \,{\left (x e + d\right )}^{\frac{5}{2}} b^{5} d^{3} e^{3} - 472 \,{\left (x e + d\right )}^{\frac{3}{2}} b^{5} d^{4} e^{3} + 213 \, \sqrt{x e + d} b^{5} d^{5} e^{3} - 801 \,{\left (x e + d\right )}^{\frac{5}{2}} a b^{4} d^{2} e^{4} + 1888 \,{\left (x e + d\right )}^{\frac{3}{2}} a b^{4} d^{3} e^{4} - 1065 \, \sqrt{x e + d} a b^{4} d^{4} e^{4} + 801 \,{\left (x e + d\right )}^{\frac{5}{2}} a^{2} b^{3} d e^{5} - 2832 \,{\left (x e + d\right )}^{\frac{3}{2}} a^{2} b^{3} d^{2} e^{5} + 2130 \, \sqrt{x e + d} a^{2} b^{3} d^{3} e^{5} - 267 \,{\left (x e + d\right )}^{\frac{5}{2}} a^{3} b^{2} e^{6} + 1888 \,{\left (x e + d\right )}^{\frac{3}{2}} a^{3} b^{2} d e^{6} - 2130 \, \sqrt{x e + d} a^{3} b^{2} d^{2} e^{6} - 472 \,{\left (x e + d\right )}^{\frac{3}{2}} a^{4} b e^{7} + 1065 \, \sqrt{x e + d} a^{4} b d e^{7} - 213 \, \sqrt{x e + d} a^{5} e^{8}}{24 \,{\left ({\left (x e + d\right )} b - b d + a e\right )}^{3} b^{6}} + \frac{2 \,{\left (3 \,{\left (x e + d\right )}^{\frac{5}{2}} b^{16} e^{3} + 20 \,{\left (x e + d\right )}^{\frac{3}{2}} b^{16} d e^{3} + 150 \, \sqrt{x e + d} b^{16} d^{2} e^{3} - 20 \,{\left (x e + d\right )}^{\frac{3}{2}} a b^{15} e^{4} - 300 \, \sqrt{x e + d} a b^{15} d e^{4} + 150 \, \sqrt{x e + d} a^{2} b^{14} e^{5}\right )}}{15 \, b^{20}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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